No. I asked that ratios be averaged, and not simple whole numbers. That is not mathmatically correct.
She correctly answered the average of 30 and 51, and 30 and 60, respectively. She did not answer how to average 51 and 60 MPH for 2 miles after you have already travelled one mile at 30 MPH.
It may have been worded less than perfectly, but it most certainly wasn'yt worded in a way that would make those answers correct.
Maybe I should have said how fast the wheels were moving.
She was right on according to the way you proposed the question as a 2 part, 1 mile each, average. In other words your question seemed to ask for the average of the two equal halves of the total distance. Averaging an integer representing each mile as a whole. Clarity is a beautiful thing!
You drive your F-body 30MPH through town for 1 mile. You're late for an appoinment and you are going a total of 2 miles from your start to your destination. Now that you have 1 mile of open road to go (assume no speed limit), how fast will you need to go to average:
51 MPH (you'll be just on time)?
or
60 MPH (time to spare)?
If you're already late for the appointment, then it doesn't matter how fast you go you won't get there on time!
Dave M
Life, liberty, and the pursuit of all who threaten it!
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