i was just wondering if there was some type of formula that could calculate, how many car lengths in a race equal how much time???
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1995 z-28, six speed, centerforce d.f clutch, moser4:10,afr heads, zz-409 cam,full tubes w/ c.o.,nx direct port kit-150shot,hoosier qtp's
dyno
NA -356 rwhp, 360ft/lbs
N20 -510rwhp, 521ft/lbs -
I'm not quite sure but I think atleast in the quarter mile 1 car length equals roughly one tenth of a second. I think Joe might know a better way than that to figure it out though.1994 Firebird Formula, M6, Fan switch, 160 thermostat, Pacesetter LT headers, Morosso CAI, TB bypass, True duals. -
One way to figure it......
Depends on the speed of the vehicles. At 100 MPH, the lead vehicle is moving at 147 ft/second. That means 1/10th second difference is a 14.7 foot difference, or very close to the length of a car - a 4th Gen is 195" = 16.2 feet.
At 111 MPH, 1/10th second = exactly the length of a 4th Gen F-Body.Fred
381ci all-forged stroker - 10.8:1 - CNC LT4 heads/intake - CC solid roller - MoTeC engine management - 8 LS1 coils - 58mm TB - 78# injectors - 300-shot dry nitrous - TH400 - Gear Vendor O/D - Strange 12-bolt - 4.11's - AS&M headers - duals - Corbeau seat - AutoMeter gauges - roll bar - Spohn suspension - QA1 shocks - a few other odds 'n ends. 800HP/800lb-ft at the flywheel, on a 300-shot. 11.5 @ 117MPH straight motorComment
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